v^2-2v^2=11v+30

Solution for v^2-2v^2=11v+30 equation:

v^2-2v^2=11v+30

We move all terms to the left:

v^2-2v^2-(11v+30)=0

We add all the numbers together, and all the variables

-1v^2-(11v+30)=0

We get rid of parentheses

-1v^2-11v-30=0

a = -1; b = -11; c = -30;
Δ = b2-4ac
Δ = -112-4·(-1)·(-30)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-1}{2*-1}=\frac{10}{-2}
=-5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+1}{2*-1}=\frac{12}{-2}
=-6
$